Question

b) ( 5 + x )^2 - 36 =0

Answer 1

\(b,\left(5+x\right)^2-36=0\\ =>\left(5+x\right)^2=36\\ =>\left[{}\begin{matrix}5+x=6\\5+x=-6\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)

Answer 2

`(5+x)^2-36=0`

`=>(5+x)^2=0+36`

`=>(5+x)^2=36`

`=>(5+x)^2=6^2` hoặc `(-6)^2`

`@TH1:`

`=>5+x=6`

`=>x=6-5`

`=>x=1`

`@TH2:`

`=>5+x=-6`

`=>x=-6-5`

`=>x=-11`

Vậy `x in{1;-11}`