Question

a)

x+x:3*15=424/4+102/6

b)100-x+5*2/2-0=0

 

                 

Answer 1

a. \(x+\frac{x}{3}\cdot15=\frac{424}{4}+\frac{102}{6}\)

\(x+5x=106+17\)

\(x\left(1+5\right)=123\)

\(6x=123\)

\(x=\frac{123}{6}=\frac{41}{2}\)

Answer 2

b. \(100-x+\frac{5\cdot2}{2}-0=0\)

\(100-x+5=0\)

\(105-x=0\)

\(x=105-0=105\)