Lời giải:
a. $x(\frac{4}{5}x-1)(0,1x-10)=0$
$\Rightarrow x=0$ hoặc $\frac{4}{5}x-1=0$ hoặc $0,1x-10=0$
Nếu $\frac{4}{5}x-1=0$
$\Rightarrow x=1: \frac{4}{5}=\frac{5}{4}$
Nếu $0,1x-10=0$
$\Rightarrow x=10:0,1=100$
Vậy $x=0; \frac{5}{4}; 100$
b.
$(\frac{1}{4}x-1)-(\frac{5}{6}x+2)-(1-\frac{5}{8}x)=0$
$(\frac{1}{4}x-\frac{5}{6}x+\frac{5}{8}x)-(1+2+1)=0$
$\frac{1}{24}x-4=0$
$x=4: \frac{1}{24}=96$
BT6:
A) (5x+1)^2=16/25
B) ( x - 1/3)^3=(2/3)^6
C)(8x - 1)^4=(2x+7)^4
D) (x -1)^5 =(2x-3)^5
E) ( x +1 )^8=(x+1)^10
G) (21-3)^4+(x+5)^6=0
H) 3x -4 = 81^3
Tìm x,y biết :
a) 1-(5/3/8+x-7/5/24): 16/2/3=0
b) (1/6+2/1/12-10,75).x-7= (2/5+3/8-2,225): 0,1
tìm x
a, x2 + x = 0
b, (x-1)x+2 = (x-1)x+4
c, 1/4. 2/6. 3/8. 4/10. 5/12..... 30/62. 31/64=2x
d, x-1/ x+5= 6/7
e, x2/ 6= 24/25
g, x-2/ x-1= x+4/ x+7
Tìm x biết
a) (8-5x).(x+2)+4.(x-2).(x+1)+2.(x-2).(x+2)=0
b)\(\left(-\frac{2}{5}+x\right):\frac{7}{9}+\left(-\frac{3}{5}+\frac{5}{6}\right):\frac{7}{9}=0\)
c)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=1\frac{2003}{2004}\)
Tìm giá trị của x biết:
a) x - 3/5 = 1 - 4/5 + 1/6
b) ( - 10/4 ) + 1/4 = 3/4
c) -3/2 + ( x - 1/2 ) = 1/2
d) x - 2/7 = 7/2 1
đ) ( 1/6 + 1/10 - 1/15 ) + x = 0
B2: Tìm x
a) | x | = 3,5
b) |1-x |+ 0,73 = 3
c) -5/8 + x = 4/9
d) x.(1/5 + 1/4) - (1/7 + 1/8) =0
e) | x | + -2,7
f) |x + 3/4 | -5 = -2
1) x2019 - 1 = 0
2) x4 - 16 = 0
3) 32 - x5 = 0
4) ( x - 2 )3 = ( 1 - 3x )3
5) ( 4 - 3x )10 - ( 3 + x ) = 0
6) x2 = x
7) x6 = x3
8) ( x - 3 )5 = 4 ( x - 3 )
Câu 1 :
a) |x+5| + |3-x| = 8
b) 1/2 . (3/4 . x - 1/2)2020 + | 4/5 . y + 6/25| bé hơn hoặc bằng 0
c) (x-1)2 + (y+3)2 = 0
d) |x-3y|5 + |y+4| = 0
\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(-\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)0
b) \(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{5}x+1=0\)
