Question

a.(x-1)^x+2 = (x-1)^x+4

^{giúp với nha}

^{ai đang online thì giúp em với}

Answer 1

ta có

\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\)

\(\left(x-1\right)^{x+4}-\left(x-1\right)^{x+2}=0\)

\(\left(x-1\right)^{x+2}[\left(x-1\right)^2-1]=0\)

+, \(\left(x-1\right)^{x+2}=0\Rightarrow x-1=0\Rightarrow x=1\)

+, \(\left(x-1\right)^2-1=0\Rightarrow\left(x-1\right)^2=1\Rightarrow\orbr{\begin{cases}x-1=1\\x-1=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}}\)

Vậy...