a)\(n_{Na_2SO_4}=\dfrac{m_{Na_2SO_4}}{M_{Na_2SO_4}}=\dfrac{50}{142}\approx0,35\left(m\right)\)
b)\(n_{H_2O}=\dfrac{V_{H_2O}}{22,4}=\dfrac{18}{22,4}\approx0,8\left(m\right)\)
a)\(m_{Na_2SO_4}=\dfrac{50}{142}\approx0,35\left(m\right)\)
b)\(n_{H_2O}=\dfrac{18}{22,4}\approx0,8\left(m\right)\)