Giải phương trình:
a) \(5x^2-10x=4\left(x-1\right)\sqrt{x^2-2x+2}\)
b) \(\sqrt{2x^2+22x+29}-x-2=2\sqrt{2x+3}\)
c) \(x^3-7x^2+9x+12=\left(x-3\right)\left(x-2+5\sqrt{x-3}\right)\left(\sqrt{x-3}-1\right)\)
Mọi người giúp gấp với ạ.
Giải pt:
\(\sqrt{x^2+10x+21}=3\sqrt{x+3}+2\sqrt{x+7}-6\)
\(4\left(x+1\right)^2=\left(2x+10\right)\left(1-\sqrt{3+2x}\right)^2\)
\(\frac{1}{1-\sqrt{1-x}}-\frac{1}{1+\sqrt{1-x}}=\frac{\sqrt{3}}{x}\)
\(\sqrt{x+3}+2x\sqrt{x+1}=2x+\sqrt{x^2+4x+3}\)
\(\sqrt{x-2}+\sqrt{4-x}=x^2-6x+11\)
Giải các pt sau bằng cách đặt ẩn phụ:
a/\(-4\sqrt{\left(4-x\right)\left(2+x\right)}=x^2-2x-12\)
b/\(\left(x-3\right)^2+3x-22=\sqrt{x^2-3x+7}\)
c/\(\frac{\sqrt{x+4}+\sqrt{x-4}}{2}=x+\sqrt{x^2-16}-6\)
d/\(\sqrt{x-1}+\sqrt{x+3}+2\sqrt{\left(x-1\right)\left(x+3\right)}=4-2x\)
e/\(\sqrt{x+7}+\sqrt{7x-6}+\sqrt{49x^2+7x-42}=181-14x\)
f/\(5\sqrt{x}+\frac{5}{2\sqrt{x}}=2x+\frac{1}{2x}+4\)
GIẢI CÁC PT SAU:
\(\sqrt{x^2+5x+1}=\sqrt{x+1}\)
\(\sqrt{x^2+2x+4}=\sqrt{2-x}\)
\(\sqrt{2x+4}-\sqrt{2-x}=0\)
GIẢI PT SAU:
\(\sqrt{3x^2-2x+6}+3-2x=0\)
\(\sqrt{x+1}+\sqrt{x-1}=4\)
giải phương trình \(\frac{7x+4}{\sqrt{2x^2-2}}+2\frac{\sqrt{2x+1}}{\sqrt{2x+2}}=3+3\frac{\sqrt{2x+1}}{\sqrt{x-1}}\)
tìm điều kiện bài toán:
a) \(y=\dfrac{1}{x}-\dfrac{\sqrt{2x-1}}{x^2-3x+2}\)
b) \(y=\dfrac{1}{x^2-1}-\sqrt{7-2x}\)
c) \(y=\dfrac{2}{x}+\dfrac{3}{4-2x+x^2}\)
d) \(y=\sqrt{25-x^2}-2\sqrt{x}+3\)
1. \(\sqrt{2x^2+5x-6}>2-x\)x
2.\(\sqrt{x^2+2}\le x-1\)
3.\(\sqrt{x^2-2x-15}>2x+5\)
4.\(\left(16-x^2\right)\sqrt{x-3}\le0\)
5.\(\sqrt{x^2+2017}\le\sqrt{2018}x\)
6.\(\hept{\begin{cases}\frac{x+3}{2x-3}-\frac{x}{2x-1}\le0\\\sqrt{x^2+3}+3x< 1\end{cases}}\)
xác định hàm số
a, \(y=\sqrt{x^2+x-4}\)
b , \(y=\frac{1}{x^2+1}\)
c, y= l 2x - 3 l
d , \(y=\frac{1}{x^2-3x}\)
e , \(y=\sqrt{1-x}+\frac{1}{x\sqrt{1}+x}\)
f , \(y=\frac{2x-1}{\sqrt{x\sqrt{\left(x-4\right)}}}\)
g , \(y=\sqrt{3+x}+\frac{1}{x^2-1}\)
h , \(y=\frac{1}{\sqrt{2x^2-4x+4}}\)
i, \(y=\sqrt{6-x}+2x\sqrt{2x+1}\)
j, \(y=\frac{x^2+1}{\sqrt{2-5}}+x\sqrt{1+x}\)
k, \(y=\frac{1}{x^2+3x+3}+\left(x+2\right)\sqrt{x+3}\)
l, \(y=\sqrt[3]{\frac{3x+5}{x^2-1}}\)