\(A=\left(\frac{\sqrt{a}}{2}-\frac{1}{2\sqrt{a}}\right)^2\left(\frac{\sqrt{a}-1}{\sqrt{a}+1}-\frac{\sqrt{a}+1}{\sqrt{a}-1}\right)\)
\(A=\left(\frac{a-1}{2\sqrt{a}}\right)^2.\left[\frac{\left(\sqrt{a}-1\right)^2-\left(\sqrt{a}+1\right)^2}{\left(\sqrt{a}+1\right)\left(\sqrt{a}-1\right)}\right]\)
\(A=\frac{\left(a-1\right)^2}{4a}.\)\(\frac{\left(\sqrt{a}-1-\sqrt{a}-1\right)\left(\sqrt{a}-1+\sqrt{a}+1\right)}{a-1}\)
\(A=\frac{a-1}{4a}.\left(-2\right).2\sqrt{a}\)
\(A=\frac{\left(a-1\right).\left(-4\sqrt{a}\right)}{4a}\)
\(A=\frac{-\left(a-1\right)}{\sqrt{a}}\)
\(ĐKXĐ:a\ne0,1\)
\(A=\left(\frac{\sqrt{a}}{2}-\frac{1}{2\sqrt{a}}\right)^2\left(\frac{\sqrt{a}-1}{\sqrt{a+1}}-\frac{\sqrt{a}+1}{\sqrt{a}-1}\right)\)
\(A=\left(\frac{a}{4}-\frac{1}{2}+\frac{1}{4a}\right)\left(\frac{a-2\sqrt{a}+1}{a-1}-\frac{a+2\sqrt{a}+1}{a-1}\right)\)
\(A=\left(\frac{a^2-2a+1}{4a}\right)\left(\frac{-4\sqrt{a}}{a-1}\right)\)
\(A=\frac{\left(a-1\right)^2}{4a}\times\frac{-4\sqrt{a}}{a-1}\)
\(A=\frac{-4\sqrt{a}\left(a-1\right)^2}{4a\left(a-1\right)}\)
\(A=-\sqrt{a}\left(a-1\right)\)
Vậy........
k mk nha
Em thấy bước thứ 2 từ dưới lên đến hết của chị nó cứ sao sao ấy !!! :< Em thấy chị sai mà !
Sửa lại dòng cuối
\(A=\frac{-\sqrt{a}\left(a-1\right)}{a}\)
