`@` `\text {Ans}`
`\downarrow`
`A = [-1 + 3 2/5 + 1/4]*[-4]`
`= (12/5 + 1/4)*(-4)`
`= 53/20*(-4)`
`= -53/5`
Vậy, `A=-53/5.`
Đúng 2
Bình luận (0)
Các câu hỏi tương tự
a)\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}-\dfrac{1}{6}-\dfrac{4}{35}\)
b)\(\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)-\left(5+\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(-6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
c)\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
Tính giá trị của các biểu thức sau :
a)left(7+3dfrac{1}{4}-dfrac{3}{5}right)+(0,4 - 5) - left(4dfrac{1}{4}-1right)
b)dfrac{2}{3} - left[left(-dfrac{7}{4}right)-left(dfrac{1}{2}+dfrac{3}{8}right)right]
c)left(9-dfrac{1}{2}-dfrac{3}{4}right):left(7-dfrac{1}{4}-dfrac{5}{8}right)
d)3 - dfrac{1-dfrac{1}{7}}{1+dfrac{1}{7}}
giúp mình nhé trả lời mình cho tick cảm ơn các bạn !
Đọc tiếp
Tính giá trị của các biểu thức sau :
a)\(\left(7+3\dfrac{1}{4}-\dfrac{3}{5}\right)\)+(0,4 - 5) - \(\left(4\dfrac{1}{4}-1\right)\)
b)\(\dfrac{2}{3}\) - \(\left[\left(-\dfrac{7}{4}\right)-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\)
c)\(\left(9-\dfrac{1}{2}-\dfrac{3}{4}\right)\):\(\left(7-\dfrac{1}{4}-\dfrac{5}{8}\right)\)
d)3 - \(\dfrac{1-\dfrac{1}{7}}{1+\dfrac{1}{7}}\)
giúp mình nhé trả lời mình cho tick cảm ơn các bạn !
\(A=\dfrac{\left(17\dfrac{1}{4}-4\dfrac{3}{16}-13\dfrac{5}{6}\right).\left(\dfrac{-4}{7}\right)+6\dfrac{3}{4}}{\left(5\dfrac{2}{7}-\dfrac{16}{3}\right):\left(6\dfrac{2}{3}-4\dfrac{1}{2}\right)}\)
3dfrac{3}{3}.dfrac{1}{3}-dfrac{3}{4}.dfrac{1}{3}left[dfrac{11}{3}right]-left(dfrac{-1}{2}right)^2-4dfrac{1}{2}left(dfrac{3}{2}-dfrac{5}{4}+dfrac{1}{3}right):left(dfrac{4}{3}+2dfrac{3}{2}-dfrac{3}{4}right)5dfrac{5}{27}+dfrac{7}{23}+0,5+dfrac{-5}{27}+dfrac{16}{23}2dfrac{5}{4}+left(-2018right)^0-left[dfrac{-1}{4}right]dfrac{19}{11}.dfrac{6}{5}+dfrac{6^2}{11}.dfrac{6}{5}-left(dfrac{1}{2}right)^0
Đọc tiếp
\(3\dfrac{3}{3}.\dfrac{1}{3}-\dfrac{3}{4}.\dfrac{1}{3}\)
\(\left[\dfrac{11}{3}\right]-\left(\dfrac{-1}{2}\right)^2-4\dfrac{1}{2}\)
\(\left(\dfrac{3}{2}-\dfrac{5}{4}+\dfrac{1}{3}\right):\left(\dfrac{4}{3}+2\dfrac{3}{2}-\dfrac{3}{4}\right)\)
\(5\dfrac{5}{27}+\dfrac{7}{23}+0,5+\dfrac{-5}{27}+\dfrac{16}{23}\)
\(2\dfrac{5}{4}+\left(-2018\right)^0-\left[\dfrac{-1}{4}\right]\)
\(\dfrac{19}{11}.\dfrac{6}{5}+\dfrac{6^2}{11}.\dfrac{6}{5}-\left(\dfrac{1}{2}\right)^0\)
-2/5 : \(1\dfrac{1}{3}\)- ( 1/2 )\(^2\)
\(\left(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{5}{6}\right).\left(\dfrac{-3}{2}\right)^2\)
\(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right).\left(\dfrac{4}{5}-\dfrac{3}{4}\right)^2\)
Tính
a) \(\dfrac{13}{50}.\left(-15.5\right):\dfrac{13}{50}.84\dfrac{1}{2}\)
b) \(\dfrac{\left(-0,7\right)^2.\left(-5\right)^3}{\left(-2\dfrac{1}{3}\right)^3.\left(1\dfrac{1}{2}\right)^4.\left(-1\right)^5}\)
Tìm x :
1) \(\left(-0,75x+\dfrac{5}{2}\right).\dfrac{4}{7}-\left(-\dfrac{1}{3}\right)=-\dfrac{5}{6}\)
2) \(\left(4x-9\right)\left(2,5+\dfrac{-7}{3}x\right)=0\)
3) \(\left|x-\dfrac{3}{4}\right|-\dfrac{1}{2}=0\)
4)\(\left(\dfrac{3}{5}-\dfrac{2}{3}x\right)^3=\dfrac{-64}{125}\)
Tính:
a/\(A=\left(-0,75-\dfrac{1}{4}\right):\left(-5\right)+\dfrac{1}{48}-\left(\dfrac{-1}{6}\right):\left(-3\right)\)
b/\(B=\left(\dfrac{6}{25}-1,24\right):\dfrac{3}{7}:\left[\left(3\dfrac{1}{2}-3\dfrac{2}{3}\right):\dfrac{1}{14}\right]\)
Bài 1:
a,3^7 : 3^5- left(dfrac{5}{17}right)^0 b,left(dfrac{5}{2}right)^{13} : left(dfrac{1}{2}+2right)^3 c, 8.left(dfrac{1}{4}right)^3 +left(dfrac{2}{27}right)^0 - dfrac{1}{8}
Bài 2 :
a, dfrac{3^4.4^4}{6^4} b,dfrac{15^3}{10^3} c, dfrac{4^2.12^5}{9^2.2^{10}} d, dfrac{6^2+5.2^2+4}{15}
Bài 3 :
a, dfrac{left(dfrac{2}{3}right)^3.left(dfrac{-3}{4}right)^2.left(-1right)^5}{left(dfrac{2}{5}right)^2.left(dfrac{-5}{12}right)^2} b,dfrac{6^6+6^3.3^3+3^6}{-73}
Mọi người giúp mình nhé mình sẽ ch...
Đọc tiếp
Bài 1:
a,\(3^7\) : \(3^5\)- \(\left(\dfrac{5}{17}\right)^0\) b,\(\left(\dfrac{5}{2}\right)^{13}\) : \(\left(\dfrac{1}{2}+2\right)^3\) c, 8.\(\left(\dfrac{1}{4}\right)^3\) +\(\left(\dfrac{2}{27}\right)^0\) - \(\dfrac{1}{8}\)
Bài 2 :
a, \(\dfrac{3^4.4^4}{6^4}\) b,\(\dfrac{15^3}{10^3}\) c, \(\dfrac{4^2.12^5}{9^2.2^{10}}\) d, \(\dfrac{6^2+5.2^2+4}{15}\)
Bài 3 :
a, \(\dfrac{\left(\dfrac{2}{3}\right)^3.\left(\dfrac{-3}{4}\right)^2.\left(-1\right)^5}{\left(\dfrac{2}{5}\right)^2.\left(\dfrac{-5}{12}\right)^2}\) b,\(\dfrac{6^6+6^3.3^3+3^6}{-73}\)
Mọi người giúp mình nhé mình sẽ cho bạn 1 like
A=\(\left[\dfrac{1\dfrac{11}{31}.4\dfrac{3}{7}-\left(15-6\dfrac{1}{3}.\dfrac{2}{19}\right)}{4\dfrac{5}{6}+\dfrac{1}{6}\left(12-5\dfrac{1}{3}\right)}.\left(-1\dfrac{14}{93}\right)\right].\dfrac{31}{50}\)