Question

Ai giúp mình với

Answer 1

Ta có: \(2x^3-1=15\)

\(2x^3=15+1\)

\(2x^3=16\)

\(x^3=16:2\)

\(x^3=8\)

\(x^3=2^3\)

\(\Rightarrow x=2\)

Khi đó: \(\dfrac{2+16}{9}=\dfrac{y-25}{16}=\dfrac{z+9}{16}\)

\(\Rightarrow\dfrac{y-25}{16}=\dfrac{z+9}{16}=2\)

\(\Rightarrow\left\{{}\begin{matrix}y-25=2\cdot16=32\\z+9=2\cdot16=32\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}y=57\\z=23\end{matrix}\right.\)

Suy ra: \(A=x+y+z=2+57+23=82\)