\(A=1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+...+\frac{1}{2011}\left(1+2+3+...+2011\right)\)
\(=1+\frac{1}{2}\cdot\frac{2.3}{2}+\frac{1}{3}\cdot\frac{3.4}{2}+...+\frac{1}{2011}\cdot\frac{2011.2012}{2}\)
\(=\frac{2}{2}+\frac{3}{2}+\frac{4}{2}+...+\frac{2012}{2}\)
\(=\frac{2+3+4+...+2012}{2}\)
\(=\frac{\frac{2012\cdot2013}{2}-1}{2}=\frac{2025077}{2}\)
Giup mik bai nay nha : |x|=(-1/2)^2-1^2011+2/4×(-1/2)+√25/16
Các ban giúp mình giải bài này với
Tính A=\(1+\frac{1}{2}\left(1+2\right)+\frac{1}{3}\left(1+2+3\right)+....+\frac{1}{2011}\left(1+2+3+...+2011\right)\)
\(Giai\)\(giup\)\(minh\)help me
\(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{2011}}{\frac{2010}{1}+\frac{2009}{2}+\frac{2008}{3}+....+\frac{1}{2010}}\)
Cac ban giai giup minh voi minh minh kiem tr roi
giai co loi giai nha
minh kich dung cho
Cho:
A=1/2+1/3+1/4+...+1/200
B = 1/199+2/198+3/197+...+ 197/3+198/2+199/1
Tinh A/B
Bai nay kho nen cac ban giai giup minh nha minh tich dung cho
\(\left(x-2011\right)^{x+1}-\left(x-2011\right)^{x+2011}=0\)
Lam bai co loi giai giup minh nha
ai giai giup minh bai nay voi
Cho2011 so khac 0:\(a_1;a_2;.....;a_{2011}\) thoa man \(a_2^2=a_1.a_3;a_3^2=a_2.a_4;.......;a_{2010}^2=a_{2009}.a_{2011}\)
CMR:\(\frac{a_1^{2010}+a_2^{2010}+.....+a_{2010}^{2010}}{a_2^{2010}+a_3^{2010}+.....+a_{2011}^{2010}}=\frac{a_1}{a_{2011}}\)
giai giup minh voi minh tick cho
ai đó giúp mk với mk xin chân thành cảm ơn! a=(2010+2010/2+2009/3+2008/4+...+1/2011/ 1/2+1/3+...+1/2011) / (1/2+1/3+1/4+1/5+...+1/2009+1/2010+1/2011)
Tim gia tri nho nhat
A=/x-2010/+/x-2011/
B=/x-1/+/x-2/+/x-3/+2011
C=5\(x^2\)+20x+2010
cac ban giai va cach trinh bay nhe
minh kich dung cho
giai giup minh voi
ai giai giup minh bai nay voi
Cho2011 so khac 0:\(a_1;a_2;.....;a_{2011}\) thoa man \(a_2^2=a_1.a_3;a_3^2=a_2.a_4;.......;a_{2010}^2=a_{2009}.a_{2011}\)
CMR:\(\frac{a_1^{2010}+a_2^{2010}+.....+a_{2010}^{2010}}{a_2^{2010}+a_3^{2010}+.....+a_{2011}^{2010}}=\frac{a_1}{a_{2011}}\)
