Ta có: \(m_{gi\text{ả}m}=m_{CO_2}=3,8\left(g\right)\)
=> \(n_{CO_2}=\dfrac{m}{M}=\dfrac{3,8}{44}=\dfrac{19}{220}\left(mol\right)\)
PTHH: \(CaCO_3\xrightarrow[]{t^o}CaO+CO_2\)
Theo PT: \(n_{CaCO_3}=n_{CO_2}=\dfrac{19}{220}\left(mol\right)\)
=> \(m_{CaCO_3}=n.M=\dfrac{19}{220}.100=\dfrac{95}{11}\approx8,64\left(g\right)\)