b; \(3\frac{1}{4}.x-1\frac{1}{6}.x-1\frac{2}{3}=\frac{5}{12}\)
\(\Rightarrow x.\left(3\frac{1}{4}-1\frac{1}{6}-1\frac{2}{3}\right)=\frac{5}{12}\)
\(\Rightarrow x.\left(\frac{13}{4}-\frac{7}{6}-\frac{5}{3}\right)=\frac{5}{12}\)
\(\Rightarrow x.\left(\frac{39}{12}-\frac{14}{12}-\frac{20}{12}\right)=\frac{5}{12}\)
\(\Rightarrow x.\frac{5}{12}=\frac{5}{12}\)
\(\Rightarrow x=\frac{5}{12}\div\frac{5}{12}=1\)
Vậy x=1
a, 8/8 x - 2/3 = 1/3 x + 4/3
<=> x -1/3 x = 4/3 + 2/3
<=> 2/3 x = 2
<=> x = 2 : 2/3
<=> x = 3
Vậy x = 3 .
b, <=> 13/4 x - 7/6 x = 5/12 +5/3
<=> 25/12 x = 25/12
<=> x = 25/12 : 25/12
<=> x = 1