\(A=\frac{17^{20}+2}{17^{20}-1}=\frac{17^{20}-1+3}{17^{20}-1}=1+\frac{3}{17^{20}-1}\)
\(B=\frac{17^{20}-2}{17^{20}-5}=\frac{17^{20}-5+3}{17^{20}-5}=1+\frac{3}{17^{20}-5}\)
Vì \(17^{20}-1>17^{20}-5\)
\(=>\frac{3}{17^{20}-1}1+\frac{3}{17^{20}-1}
\(A=\frac{17^{20}+2}{17^{20}-1}=\frac{17^{20}-1+3}{17^{20}-1}=1+\frac{3}{17^{20}-1}\)
\(B=\frac{17^{20}-2}{17^{20}-5}=\frac{17^{20}-5+3}{17^{20}-5}=1+\frac{3}{17^{20}-5}\)
Vì \(17^{20}-1>17^{20}-5\)
\(=>\frac{3}{17^{20}-1}1+\frac{3}{17^{20}-1}
\(\left(\frac{1}{4}\right)^{44}:\left(\frac{1}{2}\right)^{12}\)
\(\left(\frac{3^{17}-81^{11}}{37^{10}.9^{17}}\right)\)
\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
so sánh:
a,\(3^{34}v\text{à5}^{20}\)
b,\(71^5v\text{à}17^{20}\)
1.Tìm x :
a)1 - 7x = 3x - 4
2.Tính
a)-2013 . 2028 + 4028 . 26
b)\(\left(\frac{1515}{1616}+\frac{10}{170}\right)-\left(\frac{150}{160}-\frac{16}{17}\right)\)
c)\(\frac{1}{3^1}+\frac{1}{3^2}+\frac{1}{3^3}+...\frac{1}{3^{99}}\)
d)\(\frac{5}{17}+\frac{-4}{7}-\frac{20}{31}+\frac{12}{17}-\frac{11}{31}\)
e)\(\frac{155-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{20}{7}-\frac{13}{13}_{ }+\frac{13}{23}}\)
\(\left(x-\frac{2}{5}\right).\frac{3}{4}+1=\frac{17}{20}\)
Tìm x biết
\frac{15}{11\cdot 14}+\frac{15}{14\cdot \:17}+\frac{15}{17\cdot \:20}+...+\frac{15}{68\cdot \:71}
Viết các biểu thức sau dưới dạng lũy thừa của một số hữu tỉ :
1)\(\frac{8^{11}.3^{17}}{27^{10}.9^{15}}\)
2)\(\frac{\left(5^4-5^3\right)^3}{125^4}\)
3)\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)
Tìm x, biết:
a) 3/(x+2)(x+5) + 5/(x+5)(x+10) + 7/ (x+10)(x+7) = x/(x+2)(x+17) với x thuộc {-2,-5,-10,-17}
b) 2/(x-1)(x-3 + 5/(x-3)(x-8) + 12/(x-8)(x-20) -1/x-20 =-3/4 với x thuộc {1,3,8,,20}
\(-2\frac{1}{5}\&\frac{110}{-50};\frac{17}{20}\&0,75\)
so sánh số hữu tỉ giúp mk vs
TÌM x BIẾT:
a,\(\frac{3}{\left(x+2\right)\left(x+5\right)}+\frac{5}{\left(x+5\right)\left(x+10\right)}+\frac{7}{\left(x+10\right)\left(x+17\right)}=\frac{x}{\left(x+2\right)\left(x+17\right)}\)
với x\(\notin\){-2;-5;-10;-17}
b,\(\frac{2}{\left(x-1\right)\left(x-3\right)}+\frac{5}{\left(x-3\right)\left(x-8\right)}+\frac{12}{\left(x-8\right)\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)
với x\(\notin\){1;3;8;20}
c, TÌM X BIẾT:
\(\frac{x-1}{2009}+\frac{x-2}{2008}=\frac{x-3}{2007}+\frac{x-4}{2006}\)
GIÚP MÌNH CHÚT NHA MÌNH CẦN NGAY. THANKS!