Question

a,|\(\dfrac{x}{2}-\dfrac{1}{3}\)| = \(\dfrac{3}{2}\)

b, \(\dfrac{3}{2}-\dfrac{1}{2}\) ( 2x-1)=\(\dfrac{3}{4}\)

c, |x-1|+2x=2

Answer 1

a,|$\frac{x}{2}-\frac{1}{3}$| = $\frac{3}{2}$

b, $\frac{3}{2}-\frac{1}{2}$ ( 2x-1)=$\frac{3}{4}$

c, |x-1|+2x=2

Answer 2

a)\(\left|\dfrac{x}{2}-\dfrac{1}{3}\right|=\dfrac{3}{2}\)

TH1

\(\dfrac{x}{2}-\dfrac{1}{3}=\dfrac{3}{2}\)

=>\(\dfrac{x}{2}=\dfrac{11}{6}\)

=>x=\(\dfrac{11.2}{6}\)

=>x=\(\dfrac{11}{3}\)

TH2

\(\dfrac{x}{2}-\dfrac{1}{2}=-\dfrac{3}{2}\)

=>\(\dfrac{x}{2}=-\dfrac{3}{2}+\dfrac{1}{2}\)

=>\(\dfrac{x}{2}=-1\)

=>x=-2