Question

\(\dfrac{2}{3}x-1\dfrac{2}{5}=\dfrac{1}{2}x+0,8\left(3\right)\)

Answer 1

$\frac{2}{3}x-1\frac{2}{5}=\frac{1}{2}x+0,8\left(3\right)$

$\frac{2}{3}x-1\frac{2}{5}=\frac{1}{2}x+\mathrm{\backslash (\backslash dfrac\{5\}\{6\}\backslash )}$

$\mathrm{=>\; \backslash (\backslash dfrac\{2\}\{3\}x-\backslash dfrac\{1\}\{2\}x=\backslash dfrac\{5\}\{6\}+\backslash dfrac\{7\}\{5\}\backslash )}$

=> \(\dfrac{1}{6}x=\dfrac{63}{30}\)

=> \(x=\dfrac{63}{30}:\dfrac{1}{6}\)

=> \(x=\dfrac{67}{5}\)

Vậy : x= 67 / 5

Answer 2

\(\dfrac{2}{3}x-1\dfrac{2}{5}=\dfrac{1}{2}x+0,8\left(3\right)\)

\(\Leftrightarrow\dfrac{2}{3}x-\dfrac{1}{2}x=0,8\left(3\right)+1\dfrac{2}{5}\)

\(\Leftrightarrow\dfrac{1}{6}x=\dfrac{67}{30}\)

\(\Leftrightarrow x=\dfrac{67}{5}\)

Vậy \(x=\dfrac{67}{5}\)