\(\overline{abcd}+4707=\overline{bcda}\)
\(\Rightarrow1000xa+\overline{bcd}+4707=10x\overline{bcd}+a\)
\(\Rightarrow999xa+4707=9x\overline{bcd}\)
\(\Rightarrow111xa+523=\overline{bcd}\)
Ta có \(\overline{bcd}\le999\Rightarrow111xa+523\le999\Rightarrow111xa\le999-523=476\)
\(\Rightarrow a\le4\)
+ Với \(a=0\Rightarrow\overline{bcd}=523\)
+ Với \(a=1\Rightarrow\overline{bcd}=111+523=634\)
+ Với \(a=2\Rightarrow\overline{bcd}=222+523=745\)
+ Với \(a=3\Rightarrow\overline{bcd}=333+523=856\)
+ Với \(a=4\Rightarrow\overline{bcd}=444+523=967\)