a) \(5-3x=6x-7\)
\(5=6x-7+3x\)
\(9x-7=5\)
\(9x=5+7=12\)
\(x=\frac{12}{9}=\frac{4}{3}\)
Vậy \(x=\frac{4}{3}\)
b) \(11-2x=x-1\)
\(11=x-1+2x\)
\(3x-1=11\)
\(3x=12\)
\(x=12:3=4\)
Vậy \(x=4\)
c) \(15-8x=9-5x\)
\(15=9-5x+8x\)
\(9+3x=15\)
\(3x=15-9=6\)
\(x=6:3=2\)
Vậy \(x=2\)