Question

A=[5-2/5+1/7]-[3+4/5-9-5/7]-[1-(-4/5)-6/7]

 

Answer 1

\(A=\left(5-\dfrac{2}{5}+\dfrac{1}{7}\right)-\left(3+\dfrac{4}{5}-9-\dfrac{5}{7}\right)-\left(1+\dfrac{4}{5}-\dfrac{6}{7}\right)\)

\(=5-\dfrac{2}{5}+\dfrac{1}{7}+6-\dfrac{4}{5}+\dfrac{5}{7}-1-\dfrac{4}{5}+\dfrac{6}{7}\)

\(=10-2+\dfrac{12}{7}\)

\(=\dfrac{68}{7}\)

Answer 2

=> 5−25+17+6−45+57−1−45+67=5−25+17+6−45+57−1−45+67

= >687

Answer 3

A = \(\left[5-\dfrac{2}{5}+\dfrac{1}{7}\right]-\left[3+\dfrac{4}{5}-9-\dfrac{5}{7}\right]-\left[1-\left(-\dfrac{4}{5}\right)-\dfrac{6}{7}\right]\)

   = \(\left[5-\dfrac{2}{5}+\dfrac{1}{7}\right]-\left[\dfrac{4}{5}-6-\dfrac{5}{7}\right]-\left[1+\dfrac{4}{5}-\dfrac{6}{7}\right]\)

   = \(5-\dfrac{2}{5}+\dfrac{1}{7}-\dfrac{4}{5}+6+\dfrac{5}{7}-1-\dfrac{4}{5}+\dfrac{6}{7}\)

   = \(10-2+\dfrac{12}{7}\)

   = \(\dfrac{68}{7}\)