Question

A=2010 x2011-1945/2010x2010+65

B=2001x2001+111/2001x2002-1890

So sánh A và B

Chú thích A và B là phân số

Answer 1

A = 2010 × 2011 - 1945 / 2010 × 2010 + 65

A = 2010 × 2010 + ( 2010 - 1945) / 2010 × 2010 + 65

A = 2010 × 2010 + 65 / 2010 × 2010 + 65

A = 1

B = 2001 × 2001 + 111 / 2001 × 2002 - 1890

B = 2001 × 2001 + 111 / 2001 × 2001 + ( 2001 - 1890)

B = 2001 × 2001 + 111 / 2001 × 2001 + 111

B = 1

=> A = B

Answer 2

b=1

a=1

a=b

:}

Answer 3

                                                  Bài làm  :

Ta có : 
\(+A=\frac{2010\times2011-1945}{2010\times2010+65}\)

\(A=\frac{2010\times2010+2010-1945}{2010\times2010+65}\)

\(A=\frac{2010\times2010+\left(2010-1945\right)}{2010\times2010+65}\)

\(A=\frac{2010\times2010+65}{2010\times2010+65}\)

\(A=1\)

\(+B=\frac{2001\times2001+111}{2001\times2002-1890}\)

\(B=\frac{2001\times2001+111}{2001\times2001+2001-1890}\)

\(B=\frac{2001\times2001+111}{2001\times2001+\left(2001-1890\right)}\)

\(B=\frac{2001\times2001+111}{2001\times2001+111}\)

\(B=1\)

Vậy A=B=1.

Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 4

\(A=\frac{2010\times2011-1945}{2010\times2010+65}\)

\(=\frac{2010\times2010+2010-1945}{2010\times2010+65}\)

\(=\frac{2010\times2010+65}{2010\times2010+65}\)

\(=1\)

\(\Rightarrow A=1\)

\(B=\frac{2001\times2001+111}{2001\times2002-1890}\)

\(=\frac{2001\times2001+111}{2001\times2001+2001-1890}\)

\(=\frac{2001\times2001+111}{2001\times2001+111}\)

\(=1\)

\(\Rightarrow B=1\)

Vậy A = B = 1

Chúc bạn học tốt

Answer 5

A.2010x(2010+1)-1945/2010x2010+65

2010x2010+2010x1-1945/2010x2010+65

2010×2010+2010-1945/2010x2010+65

2010×2010+65/2010×2010+65

1