Lời giải:
a. \(\frac{2.6^4-3^2.56}{4^2.135}=\frac{2^5.3^4-2^3.3^2.7}{2^4.135}\\ =\frac{2^3.3^2(2^2.3^2-7)}{2^4.135}=\frac{2^3.3^2.29}{2^4.3^3.5}=\frac{29}{30}\)
b.
$\frac{2}{5}+x=\frac{-1}{2}$
$x=\frac{-1}{2}-\frac{2}{5}=\frac{-9}{10}$
c.
$x.\frac{-1}{3}-\frac{1}{12}=\frac{1}{4}$
$x.\frac{-1}{3}=\frac{1}{4}+\frac{1}{12}=\frac{1}{3}$
$x=\frac{1}{3}: \frac{-1}{3}=-1$
d.
$\frac{x-2}{3}=\frac{2x+1}{5}$
$\Rightarrow 5(x-2)=3(2x+1)$
$\Rightarrow 5x-10=6x+3$
$\Rightarrow x=-13$