\(A=1+2+2^2+2^3+...+2^{2019}\\ 2A=2+2^2+2^3+2^4+...+2^{2020}\\ 2A-A=\left(2+2^2+2^3+2^4+...+2^{2020}\right)-\left(1+2+2^2+2^3+...+2^{2019}\right)\\ A=2^{2020}-1\)
A=2020/20192+1 + 2020/20192+2 + 2020/20192+3 + ... + 2020/20192+2019. CMR 1<A<2.
tính A=(1/2+1/2^2+1/2^3 +.....+1/2^2019):(1-1/2^2019)
A = 1 + 1/2(1+2) + 1/3(1 + 2 + 3) + 1/4(1 + 2 + 3 + 4) + ..........+ 1/2019(1 + 2 + 3 + 4 + .... + 2019)
1/2 = 1 phần hai
Cho A=2020/20192+1 + 2020/20192+2 + 2020/20192+3 + ... + 2020/20192+2019. CMR 1<S<2.
Giúp tôi với! Tôi sẽ tick cho
Cho A = 2^2018 / 2^2018 + 3^2019 +3^2019/ 3^2019 + 5 ^ 2020 +5^2020 / 5^2020 + 2^2018
B=1/1*2+1/3*4+1/5*6+. . . +1/2019*2020
So sánh A và B
Giúp mk, mk kick cho
Cho A= \(\frac{2020}{2019^2+1}+\frac{2020}{2019^2+2}+\frac{2020}{2019^2+3}+...+\frac{2020}{2019^2+2019}\)
Chứng minh rằng A ko thể là số tự nhiên.
Cho A=2020/20192+1 + 2020/20192+2 + 2020/20192+3 + ... + 2020/20192+2019. CMR A không là STN(Gợi ý: CMR 1<S<2)
Please help me, T3 tuần sau nộp rồi!
Cảm ơn trước nhé!
\(A=\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{2019}}\right):\left(1-\frac{1}{2^{2019}}\right)\)
A=1/2019(2/1+3/2+4/3+....+2020/2019)
Cm A không thuộc Z
Câu 1:
a, Tính A= (-1)*(-1)^2*(-1)^3*(-1)^4.....(-1)^2018*(-1)^2019.
b, Tính tổng S= 1*2*3+2*3*4+...+2018*2019*2020
