\(a,\left(1+\dfrac{1}{2}-\dfrac{1}{4}\right)^2\cdot\left(2+\dfrac{3}{7}\right)\)
\(=\left(\dfrac{4}{4}+\dfrac{2}{4}-\dfrac{1}{4}\right)^2\cdot\left(\dfrac{14}{7}+\dfrac{3}{7}\right)\)
\(=\left(\dfrac{5}{4}\right)^2\cdot\dfrac{17}{7}\)
\(=\dfrac{25}{16}\cdot\dfrac{17}{7}\)
\(=\dfrac{425}{112}\)
\(---\)
\(b,4:\left(\dfrac{1}{2}-\dfrac{1}{3}\right)^3\)
\(=4:\left(\dfrac{3}{6}-\dfrac{2}{6}\right)^3\)
\(=4:\left(\dfrac{1}{6}\right)^3\)
\(=4:\dfrac{1}{216}\)
\(=4\cdot216\)
\(=864\)
#\(Toru\)
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