`a)P=(x-3)^2+(3x+7)(x+1)`
`P=x^2-6x+9+3x^2+3x+7x+7`
`P=4x^2+4x+1+15`
`P=(2x+1)^2+15`
Vì `(2x+1)^2 >= 0 AA x<=>(2x+1)^2+15 >= 15 AA x`
Hay `P >= 15 AA x`
Dấu "`=`" xảy ra `<=>2x+1=0<=>x=-1/2`
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`b)Q=8x-x^2-6`
`Q=-(x^2-8x+6)`
`Q=-(x-4)^2+10`
Vì `-(x-4)^2 <= 0 AA x<=>-(x-4)^2+10 <= 10 AA x`
Hay `Q <= 10 AA x`
Dấu "`=`" xảy ra `<=>x-4=0<=>x=4`