150 + 1,03 : [ 10,3 . ( x - 1 ) ] = 160
1,03 : [ 10,3 . ( x - 1 ) ] = 160 - 150
1,03 : [ 10,3 . ( x - 1 ) ] = 10
[ 10,3 . ( x - 1 ) ] = 1,03 : 10
[ 10,3 . ( x - 1 ) ] = 0,103
( x - 1 ) = 0,103 : 10,3
( x - 1 ) = 0,01
x = 0,01 + 1
x = 1,01
b) Từ đề bài ,ta có: \(\hept{\begin{cases}\frac{-\left(x+3\right)}{27}=\frac{-121}{33}\left(1\right)\\\frac{11}{1-2y}=\frac{-121}{33}\left(2\right)\end{cases}}\)
Giải (1):
\(\frac{-\left(x+3\right)}{27}=\frac{-121}{33}=>-\left(x+3\right)=-121.27:33=-99=>-x-3=-99=>-x=-96=>x=96\)
Giải (2) :
\(\frac{11}{1-2y}=\frac{-121}{33}=>1-2y=11.33:\left(-121\right)=-3=>2y=4=>y=2\)
Vậy x=96;y=2