=> (x - 1)2 = 64 => (x - 1)2 = 82 => x - 1 = 8 => x = 9
b/ => x2 - x = 0
=> x(x - 1) = 0
=> x = 0 hoặc x - 1 = 0 => x = 1
a) 2 . (x - 1)2 = 128
(x - 1)2 = 64 = + 8
=> x = 9 hoặc x = -7
b) x2 = x
<=> x \(\in\) {0; -1; 1}
=> (x - 1)2 = 64 => (x - 1)2 = 82 => x - 1 = 8 => x = 9
b/ => x2 - x = 0
=> x(x - 1) = 0
=> x = 0 hoặc x - 1 = 0 => x = 1
a) 2 . (x - 1)2 = 128
(x - 1)2 = 64 = + 8
=> x = 9 hoặc x = -7
b) x2 = x
<=> x \(\in\) {0; -1; 1}
Tìm số tự nhiên x biết rằng:
a ) 2 x . 4 = 128 b ) x 15 = x
c ) ( x - 5 ) 4 = ( x - 5 ) 6 d ) x 2018 = x 2
Tim X
3) -12 + (2x – 9) + x= 0
4) 11 + (15 - x) = 1
5) 4 - (27 - 3) = x - (13 - 4)
6) 8 - (x - 10) = 23 - (- 4 +12)
7) 105 – 5(10 – 5x) = -20
8) (x -1)(8-2x)(3x+123) = 0
9) (x2 - 25)(x+ 10) = 0
10) x(x2+5) =
Tim cac so nguyen x,y biet:a)*x2 -3*x+1 chia het cho x+2 b)x2-xy = 5x-4y-9 c) (x2-8)*(x2-15)<0 d) (x+1)2+(y+1)2+(x-y)2=2 e) (x2-4)x2>0 ai lam truoc minh tick,mai minh di hoc rui,lam giup minh di pls Thank ban truoc ne ;(
Cau 1:
Tim x, biet: 1-4+7-10+.............-x=-75
Cau 2:
Cho x1, x2, x3, x4, x5 thuộc Z
Biết x1+ x2 + x3 + x4 + x5=0
và x1 + x2=x3+ x4= x4 + x5 =2
Tinh x3, x4 , x5
Cau 3: Tim x biet
(x+7+1) chia het cho (x+7)
Tim x :
a) (x^2+x)(x^2+x+1)=6
tim x a)2+4+6+..........+2x=210
b)(2-x)^6=(2-x)^8
c)x+(x+1)+(x+2)+..........(x+2010)=2029099
tim x biết
a)2|x-6|+7x-2=|x-6|+7x
b)|x-3|=2x+6
c)|x+1|+|x+2|+|x+3|+..+|x+2018|=3027x
tim x
2^x . 2^x+3 = 72
tim x
a)0,25x - 2/3x = -1 1/6
b)3/4 + 1/4.x +x - 7/6 .x = 5/12
tim x biet :
a) 1/3 + 1/6 +1/10+ ...+ 2/ x*(x+1)
b) 1/2 + 1/6 +1/12 + ...+1/x=72/73