a) \(\left\{{}\begin{matrix}m_{B_1tăng}=m_{H_2O}=5,4\left(g\right)\\m_{B_2tăng}=8,8\left(g\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}n_H=2n_{H_2O}=\dfrac{2.5,4}{18}=0,6\left(mol\right)\\n_C=n_{CO_2}=\dfrac{8,8}{44}=0,2\left(mol\right)\end{matrix}\right.\)
`=>` \(n_{O\left(A\right)}=\dfrac{4,6-0,6-0,2.12}{16}=0,1\left(mol\right)\)
`=> n_C : n_H : n_O = 0,2 : 0,6 : 0,1 = 2 : 6 : 1`
`=>` CTPT của A có dạng `(C_2H_6O)_n`
`=>` \(n=\dfrac{23.2}{46}=1\)
A là `C_2H_6O`
b) \(\left\{{}\begin{matrix}m_{B_1tăng}=m_{H_2O}=3,6\left(g\right)\\m_{B_2tăng}=m_{CO_2}=8,8\left(g\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}n_H=2n_{H_2O}=\dfrac{3,6.2}{18}=0,4\left(mol\right)\\n_C=n_{CO_2}=\dfrac{8,8}{44}=0,2\left(oml\right)\end{matrix}\right.\)
`=>` \(n_{O\left(B\right)}=\dfrac{6-0,4-0,2.12}{16}=0,2\left(oml\right)\)
`=> n_C : n_H : n_O = 0,2 : 0,4 : 0,2 = 1 : 2 : 1`
`=>` CTPT của B có dạng (CH_2O)_n`
`=>` \(n=\dfrac{15.4}{30}=2\)
`=>` B là `C_2H_4O_2`
