vi 1-1/n .n+a =0/n.n+a
0 la a
=>a/n(n)+(a)=1/n-1/n+a
vi 1-1/n .n+a =0/n.n+a
0 la a
=>a/n(n)+(a)=1/n-1/n+a
Chứng tỏ \(A=\frac{1}{n\times\left(n+1\right)\times\left(n+2\right)}=\frac{\frac{1}{ }}{2}\times\left(\frac{1}{n\times\left(n+1\right)}-\frac{1}{\left(n+1\right)\times\left(n+2\right)}\right)\)với n\(\in\)N*
Cho $A=\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}\left(n\in Z;n\ge2\right)$A=142 +162 +182 +...+1(2n)2 (n∈Z;n≥2)
Chứng tỏ A$\notin$∉ N
chứng minh : \(\frac{a}{n\times\left(n+a\right)}=\frac{1}{n}-\frac{1}{n+a}\left(n;a\in Nsao\right)\)
với n thuộc N* hãy chứng tỏ rằng :
\(\frac{1}{n\left(n+1\right)\left(n+2\right)}=\frac{1}{2}\left[\frac{1}{n\left(n+1\right)}-\frac{1}{\left(n+1\right)\left(n+2\right)}\right]\)
Cho \(A=\frac{1}{4^2}+\frac{1}{6^2}+\frac{1}{8^2}+...+\frac{1}{\left(2n\right)^2}\left(n\in Z;n\ge2\right)\)
Chứng tỏ A\(\notin\) N
Chứng minh rằng :
a, \(\frac{1}{n}-\frac{1}{n+1}=\frac{1}{n\left(n+1\right)}\)
b, \(\frac{1}{n\left(n+q\right)}=\frac{1}{q}\left(\frac{1}{n}-\frac{1}{n+q}\right)\)
Chứng Minh Rằng :
\(\frac{a}{n\left(n+a\right)}=\frac{1}{n}-\frac{1}{n+a}\) \(\left(n,a\inℕ^∗\right)\)
a)Tìm số nguyên dương n thỏa mãn:
\(\frac{1}{2}.\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{n.\left(n+2\right)}\right)=\frac{2013}{2014}\)
b)tìm a sao cho
\(\left(a+\frac{1}{1.3}\right)+\left(a+\frac{1}{3.5}\right)+\left(a+\frac{1}{5.7}\right)+...+\left(a+\frac{1}{23.25}\right)=11.a+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\right)\)
Chứng minh rằng:
a)\(\frac{1.3.5...39}{21.22.23...40}=\frac{1}{2^{20}}\)
b)\(\frac{1.3.5...\left(2n-1\right)}{\left(n+1\right)\left(n+2\right)\left(n+3\right)...2n}=\frac{1}{2^n}\)với n thuộc N*