\(a,\dfrac{5}{2}\times\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{5}{6}+\dfrac{1}{4}=\dfrac{13}{12}\\ b,\dfrac{5}{2}-\dfrac{1}{3}:\dfrac{1}{4}=\dfrac{5}{2}-\dfrac{4}{3}=\dfrac{7}{6}\)
a) \(\dfrac{5}{2}\times\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{5}{6}+\dfrac{1}{4}=\dfrac{10}{12}+\dfrac{3}{12}=\dfrac{13}{12}\)
b) \(\dfrac{5}{2}-\dfrac{1}{3}:\dfrac{1}{4}=\dfrac{5}{2}-\dfrac{1}{3}\times4=\dfrac{5}{2}-\dfrac{4}{3}=\dfrac{15}{6}-\dfrac{8}{6}=\dfrac{7}{6}\)