a: \(=\dfrac{29}{6}:\dfrac{7}{2}:\dfrac{23}{4}\)
\(=\dfrac{29}{6}\cdot\dfrac{2}{7}\cdot\dfrac{4}{23}=\dfrac{116}{483}\)
b: \(=\dfrac{17}{5}\left(6+\dfrac{1}{4}+3+\dfrac{3}{4}\right)=\dfrac{17}{5}\cdot10=34\)
c: \(=\dfrac{28}{9}\left(12+\dfrac{5}{7}-9-\dfrac{5}{7}\right)=\dfrac{28}{9}\cdot3=\dfrac{28}{3}\)