Question

a) 44 (x 3)=(-5)^3×(-1^4)b) 8×(2-x)-6×(3-x)=0

Answer 1

a) \(44+\left(x+3\right)=\left(-5\right)^3.\left(-\dfrac{1}{4}\right)\)

\(\Rightarrow44+x+3=-125.\left(-\dfrac{1}{4}\right)\)

\(\Rightarrow x=\dfrac{125}{4}-47=-\dfrac{63}{4}\)

b) \(8.\left(2-x\right)-6.\left(3-x\right)=0\)

\(\Rightarrow16-8x-18+6x=0\)

\(\Rightarrow-2-2x=0\)

=> 2 + 2x = 0

=> 2x = -2

=> x = -1

Answer 2

a)  44(x-3)=(-5)³.(-1)⁴

=>44x-132=(-125).1

=>   44x    =132-125

=>   44x    = 7

=>        x   =\(\dfrac{7}{44}\)

Vậy \(x=\dfrac{7}{44}\)

b) 8(2-x)-6(3-x)=0

=>16-8x-18+6x=0

=>-2-2x            =0

=>         -2x      =2

=>            x       =2:-2=1