\(\left(\frac{3}{1.8}+\frac{3}{8.15}+\frac{3}{15.22}+...+\frac{3}{106.113}\right)-\left(\frac{25}{50.55}+\frac{25}{55.60}+...+\frac{25}{95.100}\right)\)
Giải giúp mk với!
tính (1/8+1/8.15+1/15.22+....+1/43.50)x(4-3-5-7-...-49)/217
\(\left(\frac{1}{8}+\frac{1}{8.15}+\frac{1}{15.22}+...+\frac{1}{43.50}\right).\frac{4-3-5-...-49}{217}\)
A = 9/8 - 8/9 + 3/25 + 1/4 - 5/16 + 19/25 - 1/9 + 2/25 - 1/81
B = -1/3- 8/35 - 2/9 - 1/35 + 4//5 + -4/9 + 3/7
(1/25+1/3-1/2014)/(1/3-2014+1/25+1/25*1/3/1/2014)+1/(28*2014-74)
Cho a=2.3.4.5.........25
Chứng tỏ rằng 25 số tự nhiên liên tiếp a+2;a+3;a+4;...;a+25 đều là hợp số
(12/25)^x=(5/3)^-2-(-3/5)^4
(12/25)^x=144/625
(12/25)^x=(12/25)^2
=>x=2
c/ \(\dfrac{25}{9}\) . \(\dfrac{3}{10}\) + ( \(\dfrac{-5}{3}\) )\(^2\) . \(\dfrac{7}{10}\) + | \(\dfrac{-25}{3}\) |
tính M=1/4.((3/5+3/25+3/75+3/375)/(1+1/5+1/25+1/75)+3/4
tính M=1/4.((3/5+3/25+3/75+3/375)/(1+1/5+1/25+1/75)+3/4