a: \(\dfrac{2}{3}+x+1=\dfrac{11}{3}\)
=>\(x+\dfrac{5}{3}=\dfrac{11}{3}\)
=>\(x=\dfrac{11}{3}-\dfrac{5}{3}=\dfrac{6}{3}=2\)
b: \(-\dfrac{5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
=>\(-\dfrac{5}{6}-x=\dfrac{7}{12}-\dfrac{4}{12}=\dfrac{3}{12}\)
=>\(x=-\dfrac{10}{12}-\dfrac{3}{12}=-\dfrac{13}{12}\)
c: \(-\dfrac{7}{12}-\dfrac{3}{5}-x=\dfrac{3}{4}\)
=>\(-\dfrac{35}{60}-\dfrac{36}{60}-x=\dfrac{45}{60}\)
=>\(x=-\dfrac{71}{60}-\dfrac{45}{60}=\dfrac{-116}{60}=\dfrac{-29}{15}\)
d: \(-\dfrac{11}{12}-\left(\dfrac{2}{5}-x\right)=-\dfrac{3}{4}\)
=>\(\dfrac{2}{5}-x=-\dfrac{11}{12}+\dfrac{3}{4}=-\dfrac{11}{12}+\dfrac{9}{12}=-\dfrac{2}{12}=-\dfrac{1}{6}\)
=>\(x=\dfrac{2}{5}+\dfrac{1}{6}=\dfrac{12}{30}+\dfrac{5}{30}=\dfrac{17}{30}\)
