b: \(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}=3^{14}\cdot2\)
=>x=14
c: \(\Leftrightarrow2\cdot3^{x+1}-3^x=135\)
\(\Leftrightarrow3^x\left(2\cdot3-1\right)=135\)
\(\Leftrightarrow3^x=\dfrac{135}{6-1}=27\)
=>x=3
d: =>15:(x+2)=30:10=3
=>x+2=5
=>x=3
: ⇔2⋅3x=10⋅312+8⋅312=314⋅2⇔2⋅3x=10⋅312+8⋅312=314⋅2
=>x=14
c: ⇔2⋅3x+1−3x=135⇔2⋅3x+1−3x=135
⇔3x(2⋅3−1)=135⇔3x(2⋅3−1)=135