Đề là gì bạn nhỉ?
\(16-\left(x-3\right)^2=4^2-\left(x-3\right)^2=\left(4-x-3\right)\left(4+x-3\right)\)
\(64+16y+y^2=y^2+2y4+4^2=\left(y+4\right)^2\)
\(1,24^2-0,24^2=\left(1,24-0,24\right)\left(1,24+0,24\right)=1.1,48=1,48\)
\(\frac{1}{8}-8x^3=\left(\frac{1}{2}\right)^3-\left(2x\right)^3=\left(\frac{1}{2}-2x\right)\left(\frac{1}{4}+x+4x^2\right)\)
\(100-\left(3x-y\right)^2=10^2-\left(3x-y\right)=\left(10-3x+y\right)\left(10+3x-y\right)\)
\(64x^2-\left(8x+3\right)^2\)
\(=\left(8x\right)^2-\left(8x+3\right)^2\)
\(=\left(8x-8x-3\right)\left(8x+8x+3\right)\)
\(=\left(-3\right)\left(16x+3\right)\)
\(=-48x-9\)
