a ) 1/3x + 2/5 ( x - 1 ) = 0
1/3x + 2/5x - 2/5 = 0
x . ( 1/3 + 2/5 ) = 2/5
x . 11/15 = 2/5
=> x = 6/11
Vậy x = 6/11
b ) ( 2x - 3 ) ( 6 - 2x ) = 0
=> \(\orbr{\begin{cases}2x-3=0\\6-2x=0\end{cases}}\)
=> \(\orbr{\begin{cases}2x=3\\2x=6\end{cases}}\)=> \(\orbr{\begin{cases}x=\frac{3}{2}\\x=3\end{cases}}\)
Vậy ...
c ) -2/3 - 1/3 ( 2x - 5 ) = 3/2
1/3 . ( 2x - 5 ) = -2/3 - 3/2
1/3 . ( 2x - 5 ) = -13/6
2x - 5 = -13/6 : 1/3
2x - 5 = -13/2
=> 2x = -3/2
=> x = - 3 / 4
Vậy x = -3/4