a: \(\dfrac{1}{14}:x=-\dfrac{3}{35}\)
=>\(x=-\dfrac{1}{14}:\dfrac{3}{35}=-\dfrac{1}{14}\cdot\dfrac{35}{3}=-\dfrac{5}{2\cdot3}=-\dfrac{5}{6}\)
b: \(2\dfrac{1}{5}x-\dfrac{1}{3}x=-\dfrac{56}{45}\)
=>\(x\left(\dfrac{11}{5}-\dfrac{1}{3}\right)=-\dfrac{56}{45}\)
=>\(x\cdot\dfrac{28}{15}=-\dfrac{56}{45}\)
=>\(x=-\dfrac{56}{45}:\dfrac{28}{15}=-\dfrac{56}{45}\cdot\dfrac{15}{28}=-\dfrac{2}{3}\)
c: \(\left(x+\dfrac{4}{7}\right)\left(x-\dfrac{8}{9}\right)=0\)
=>\(\left[{}\begin{matrix}x+\dfrac{4}{7}=0\\x-\dfrac{8}{9}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{4}{7}\\x=\dfrac{8}{9}\end{matrix}\right.\)
d: \(\left(3x-2\right)\left(2x-\dfrac{2}{3}\right)=0\)
=>\(\left[{}\begin{matrix}3x-2=0\\2x-\dfrac{2}{3}=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=\dfrac{1}{3}\end{matrix}\right.\)
