a
\(\rightarrow\left(10x+1\right)^2=16\\ \rightarrow\left(10x+1\right)^2=4^2hoặc\left(10x+1\right)^2=\left(-4\right)^2\)
\(\rightarrow10x+1=4hoặc10x+1=-4\)
\(TH1:10x+1=4\\ 10x=3\\ x=\dfrac{3}{10}\)
\(TH2:10x+1=-4\\ 10x=-5\\ x=-\dfrac{1}{2}\)
vậy ...
b
\(\rightarrow x^2+10x+25-x^2-6x-9=7\\ \rightarrow4x+16=7\\ 4x=-9\\ x=-\dfrac{9}{4}\)
a: =>(10x+1)2=16
=>10x+1=4 hoặc 10x+1=-4
=>10x=3 hoặc 10x=-5
=>x=3/10 hoặc x=-1/2
b: \(\Leftrightarrow x^2+10x+25-x^2-6x-9=7\)
=>4x+16=7
=>4x=-9
hay x=-9/4