=>(6x+3)^2=(2x-10)^2
=>(6x+3-2x+10)(6x+3+2x-10)=0
=>(4x+13)(8x-7)=0
=>x=7/8 hoặc x=-13/4
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Các câu hỏi tương tự
1: 3/x+1 + 2/x+2 = 5x+4/x2+ 3x + 2
2: 2/3x + 1 - 15/6x2-x-1 = 3/2x - 1
3: 9/3x - 1 - 5-x/3x2-4x+1 = 4/x+ 1
4:5/x - 2 + 2/x+4 = 3x/x2 + 2x - 8
5: 4/x+6 + 1/x - 3 = 9/x2 + 3x - 18
6:x/x-3 - 2x2 +9/2x2 - 3x - 9= 1/2x + 3
C)(2x-3)2-(2x-3)(x-10)=7
d)(3x-4)2-9(x-3)(x+3)=8
e)(3x-5)(5-3x)+9(x+1)2=30
f)(x+4)2-(x+1)(x-1)=16
Mình cần gấp
a, (x + 2)(x + 4) - x^2 = 24
b, (x + 5)(x -5) = x^2 + x
c, (2x + 3)(2x -3) = 4x(x -1)
d, (x + 2)(x^2 -2x + 4) = 9
1.giải các phương trình sau:
a, 3(2x+1)/4 - 5x+3/6 = 2x-1/3 - 3-x/4
b, 19/4 - 2(3x-5)/5 = 3-2x/10 - 3x-1/4
c, x-2*3/2+3 + x-3*5/3+5 + x-5*2/5+2 = 10
d, x-3/5*7 + x-5/3*7 + x-7/3*5 = 2(1/3 + 1/5 + 1/7)
2. giải các phương trình:
a, x-1/9 + x-2/8 = x-3/7 + x-4/6
b, (1/1*2 + 1/2*3 + 1/3*4 + ... + 1/9*10) (x-1) + 1/10x = x- 9/10
Mọi người giúp em vs ạ. Em đang cần gấp
Giảiphương trình:
a) 20((x-2)/(x+1))^2 - 5((x+2)/(x-1)) + 48((x^2 -4)/(x^2 -1))=0
b) (8x+5)^2 (4x+3)(2x+1)=9
c)(8x-7)(8x-5)(2x-1)(4x-1)=9
d)(x-9)^4 + (x-10)^4 = (19-2x)^4
Em xin cảm ơn trc ạ!!!!
Tìm x, biết:1) 2x . (x-5) -x . (2x-4) 152) (x+1) . (x+2) - (x+4) . (x+3) 63) 4x2 - 4x+5 - x . (4x-3) 1-2x4) (x+3) . (2x+1) - 2x2 4x-55) -4 . (2x-8) + (2x-1) . (4x+3) 06) -3 . (x-2) + 4 . (2x-6) - 7 . (x-9) 5 . (3-2)7) (x-2) . (x+2) -2 . (x-4) 10. 3x8) 15x . (x-2) - (5x-1) . (3x + 1) 69) (2x+4) . (x-3) - x . (2x-10) 15-20x10) (4x-2) . (3x+4) - (2x-1) . (6x+5) 100 HEPL ME !!! Cần làm gấp những bài này, ai lm dc mk tick cho ng đó nha !!! THANK YOU !!!!
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Tìm x, biết:
1) 2x . (x-5) -x . (2x-4) = 15
2) (x+1) . (x+2) - (x+4) . (x+3) = 6
3) 4x2 - 4x+5 - x . (4x-3) = 1-2x
4) (x+3) . (2x+1) - 2x2 = 4x-5
5) -4 . (2x-8) + (2x-1) . (4x+3) = 0
6) -3 . (x-2) + 4 . (2x-6) - 7 . (x-9)= 5 . (3-2)
7) (x-2) . (x+2) -2 . (x-4) = 10. 3x
8) 15x . (x-2) - (5x-1) . (3x + 1) = 6
9) (2x+4) . (x-3) - x . (2x-10) =15-20x
10) (4x-2) . (3x+4) - (2x-1) . (6x+5) = 100
HEPL ME !!! Cần làm gấp những bài này, ai lm dc mk tick cho ng đó nha !!! THANK YOU !!!!
Chứng tỏ biểu thức không phụ thuộc x:
1) (x-5)(2x+3)-2x(x-3)+x+7
2) (x-3)(x2+3x+9)-x3+7
3) (2x-1)(x+5)-x(2x+9)+6
4) (x+2)(x2-2x+4)-x3-7
5) 8x3-(2x-1)(4x2+2x+1)-5
Bài 2: Tìm x biết:1,x^2+4x+4252,(5-2x)^2-1603,(x-3)^3-(x-3)(x^2+3x+9)+9(x+1)^2154,3(x+2)^2+(2x-1)^2-7(x-3)9x+3)365,(x-3)(x^2+3x+9)+x(x+2)(2-x)16,(2x+1)^2-4(x+2)^297,(x+3)^{^{ }2}-(x-4)(x+8)1
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Bài 2: Tìm x biết:
1,x\(^2\)+4x+4=25
2,(5-2x)\(^2\)-16=0
3,(x-3)\(^3\)-(x-3)(x\(^2\)+3x+9)+9(x+1)\(^2\)=15
4,3(x+2)\(^2\)+(2x-1)\(^2\)-7(x-3)9x+3)=36
5,(x-3)(x\(^2\)+3x+9)+x(x+2)(2-x)=1
6,(2x+1)\(^2\)-4(x+2)\(^2\)=9
7,(x+3)\(^{^{ }2}\)-(x-4)(x+8)=1
Tìm x
1) (5x-7)(x-9)-(-x+3)(-5x+2)=2x(x-4)-(x-1)(2x+3)
2) (x-3)(-2x+5)-2x(x-4)+(4x-5)(x-3)=(x-2)(x-1)-(x^2-5x)
1/ \(\dfrac{x-4}{3}+2x=\dfrac{4x-2}{6}\)
2/ \(\dfrac{5x-2}{5}-2=\dfrac{1-2x}{3}\)
3/ \(\dfrac{x-2}{2}-\dfrac{2}{3}=x-1\)
4/ \(\dfrac{2x-1}{3}+\dfrac{3x-2}{4}=\dfrac{4x-3}{5}\)
5/ \(\dfrac{x-3}{9}-\dfrac{x+2}{6}=\dfrac{x+4}{18}-\dfrac{1}{2}\)