ĐK: \(x\ge-\dfrac{1}{8}\)
\(8x^2+4x+1=\sqrt{8x+1}\)
\(\Leftrightarrow16x^2+8x+2-2\sqrt{8x+1}=0\)
\(\Leftrightarrow16x^2+\left(\sqrt{8x+1}-1\right)^2=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}16x^2=0\\\sqrt{8x+1}=1\end{matrix}\right.\)
\(\Leftrightarrow x=0\left(tm\right)\)
Vậy phương trình đã cho có nghiệm \(x=0\).
Giải phương trình
a) \(\frac{4}{20-6x-2x^2}\)+ \(\frac{x^2+4x}{x^2+5x}-\frac{x+3}{2-x}+3=0\)
b)\(\frac{x+5}{x^2-5x}-\frac{x-5}{2x^2-10x}+10=\frac{x+25}{2x^2-50}\)
c) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x.\left(x-2\right)}+\frac{1}{8x-16}\)
c) \(\frac{7}{8x}+\frac{5-x}{4x^2-8x}=\frac{x-1}{2x.\left(x-2\right)}+\frac{1}{8x-16}\)
giải pt:
2(8x+7)(8x+7)(4x+3)(x+1)=7
Giải phương trình: \(96x^2-29x+2+x\sqrt{8x-1}-\sqrt[3]{4x\left(8x+1\right)}=0\)
giải pt :
1) 4x3-3x=1/2
2) 8x(2x2-1).(8x4-8x2+1)=1
3) x3-3x=\(\sqrt{x+2}\)
rut gon (x^2+2x+1)\(x-1)^2:(2x^2+4x+2)\(4x^2-8x+4)
√(8x+1) +√(46-10x) = -x^3 +5x^2 + 4x +1
3x + căn 4x^2 - 8x +4 = 1 giúp vs ạ
Giải pt
\(4x^2+9x+1=\left(4x-1\right)\sqrt{8x^2-3x-1}\)
\(4x^2-4x-10=\sqrt{8x^2-8x-10}\)
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