\(3^3=27;3^6=729\)
\(\left(8X-12\right):4=729:27\)
\(\left(8X-12\right):4=27\)
\(8X-12=27.4\)
\(8X-12=108\)
\(8X=108+12\)
\(8X=120\)
\(X=120:8\)
\(X=15\)
-[(8x - 12):4] .33=36
[(8x - 12):4] = 36:33
[(8x - 12):4] = 33
(8x - 12):4 = 27
8x - 12 = 27 x 4
8x - 12 = 108
8x = 108 + 12
8x = 120
x = 120 : 8
x = 15
-4x3+15=47
4x3 = 47-15
4x3 = 32
x3 = 32:4
x3 = 8
x = 2
-4.2x-3=125
4.2x = 125 + 3
4.2x = 128
2x = 128:4
2x = 32
x = 32:2
x = 16
\(4X^3=47-15\)
\(4X^3=32\)
\(\Rightarrow4X^3=2\)
\(4.2X=125+3\)
\(4.2X=128\)
\(8X=128\)
\(X=128:8\)
\(X=16\)
a, [(8x - 12) : 4] . 33 = 36
(8x - 12) : 4 = 36 : 33
(8x - 12) : 4 = 33
(8x - 12) : 4 = 27
8x -12 = 27 . 4
8x - 12 = 108
8x = 108 + 12
8x = 120
x = 120 : 8
x = 15
Vậy x = 15
b, 4x3 + 15 = 47
4x3 = 47 -15
4x3 = 32
x3 = 32 : 4
x3 = 8
x3 = 23
Suy ra x = 2
Vậy x = 2
c, 4.2x - 3 = 125
4.2x = 125 + 3
8x = 128
x = 128 : 8
x = 16
Vậy x = 16
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