Question

\(7^{2x}+7^{2x+3}=344\)

Giúp mik vs

mink cần gấp

Answer 1

giúp mik vs

Answer 2

\(7^{2x}+7^{2x+3}=344\)

\(\Leftrightarrow7^{2x}+7^{2x}.343=344\)

\(\Leftrightarrow7^{2x}\left(1+343\right)=344\)

\(\Leftrightarrow7^{2x}.344=344\)

\(\Leftrightarrow7^{2x}=1\)

\(\Leftrightarrow7^{2x}=7^0\)

\(\Leftrightarrow2x=0\)

\(\Leftrightarrow x=0\)

Vậy \(x=0\)

Answer 3

\(\Leftrightarrow7^{2x}\left(1+7^3\right)=344\)

\(\Leftrightarrow7^{2x}.344=344\)

\(\Leftrightarrow7^{2x}=1\)

\(\Rightarrow x=0\)

Answer 4

7^2x+7^2x+3=344

7^2x+7^2x.7³=344

7^2x.(1+7⁴)=344

7^2x.2402=344

7^2x=344:2402

Từ đây b tự làm

Answer 5

\(7^{2x}+7^{2x+3}=344\)

\(=>7^{2x}+7^{2x}.7^3=344\)

\(=>7^{2x}.\left(1+7^3\right)=344\)

\(=>7^{2x}=\frac{344}{344}=1\)

\(=>x=0\)

Answer 6

làm lại

 7^2x+7^2x+3=344

7^2x+7^2x .73=344

7^2x .(1+74 )=344

7^2x .2402=344

7^2x=344:344

7^2x=1

7^2x=7⁰

2x=0

  x=0:2

  x=0

Vậy x=0

Answer 7

vừa r đăng bị lỗi :v 

\(7^{2x}+7^{2x+3}=344\)

\(7^{2x}+7^{2x}.7^3=344\)

\(7^{2x}\left(1+7^3\right)=344\)

\(7^{2x}\left(1+343\right)=344\)

\(7^{2x}.344=344\)

\(7^{2x}=1\)

\(7^{2x}=7^0\)

\(\Leftrightarrow2x=0\Leftrightarrow x=0\)