720 : [ 41 - (2x - 5 )=40
92-x) (5x-20) =0
679;15x+364/x =17
720:(41-(2x-5) ) =40
Tìm số nguyên x :
\(720:\left[41-\left(2x+5\right)\right]=40\)
720÷[41-(2x+5)]=2²×5
720÷[41-(2x+5)]=2³×5
720 : [ 41 - ( 2x - 5 ) = 2^2 . 5
d) 720:[41-(2x-5)]=2³.5
720:[(41-(2*x-5)]=40
720:[(41-(2*x-5)]=40