\(\frac{6^3+3.6^2+3^3}{-13}=\frac{2^3.3^3+3.3^2.2^2+3^3}{-13}=\frac{3^3\left(2^3+2^2+1\right)}{-1.13}=\frac{27.13}{-1.13}=-27\)
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\(\dfrac{6^3+3.6^2+3^3}{-13}\)
=?
6^3+3.6^2+3^3 phan -13
tính
a) A = \(\dfrac{6^3+3.6^2+3^3}{-13}\)
b) B =\(\dfrac{2.8^4.27^2+4.6^9}{2^3.6^7+2^7.40.9^4}\)
c) C=\(\dfrac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{16}.6^{19}-7.2^{29}.27^6}\)
(63+3.62+33) /(-13) = ?
\(\frac{6^3+3.6^2+3^3}{-13}\)
Rút gọn:\(\frac{6^3+3.6^2+3^3}{-13}\)
a) \(\dfrac{6^3+3.6^2+3^3}{-13}\)
b) \(\dfrac{5^4.20^4}{24^5.4^5}\)
Tính:
\(\left(6^3+3.6^2+3^3\right):13\)
Tính: 63 + 3.62 + 33 / -13