\(6060:\frac{50x+20}{x}=101\)
\(\frac{50x+20}{x}=60\)
\(50x+20=60x\)
\(10x=20\)
\(x=2\)
\(6060:\frac{50x+20}{x}=101\)
\(\frac{50x+20}{x}=6060:101\)
\(\frac{50x+20}{x}=60\)
\(50x+20=60x\)
\(10x=20\)
\(x=2\)
\(60x-50x=20\)
\(6060:\frac{50x+20}{x}=101\)
\(\frac{50x+20}{x}=60\)
\(50x+20=60x\)
\(10x=20\)
\(x=2\)
\(6060:\frac{50x+20}{x}=101\)
\(\frac{50x+20}{x}=6060:101\)
\(\frac{50x+20}{x}=60\)
\(50x+20=60x\)
\(10x=20\)
\(x=2\)
\(60x-50x=20\)
Tìm x biết 6060 . 50.x+20/x = 101
Tìm x
6060 : [( 50x + 20 ) : x ] = 101
\(\frac{10}{11}x\frac{12}{13}:\frac{50}{51}-\frac{19}{20}x\frac{12}{13}:\frac{101}{102}+\frac{99}{100}\)
x+2.x+3.x+4.x+...+100.x=6060
( 1 + 2 + 4 + 6 + 8 + ... + 512 ) x ( 101 x 102 - 101 x 101 - 50 - 51 )
2020 x 0,56 + 0,34 x 6060 + 8080 x 0,85 + 2020 x 5,02 =
2020 x 0,56 + 0,36 x 6060 + 8080 x 0,85 + 2020 x 5,02
x+(x+1)+(x+2)+(x+3)+...+(x+100)=6060
Bài 7 : Không tính trực tiếp hãy so sánh
A = 101 x 50
B = 50 x 49 + 53 x 50