\(6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}.\left(\frac{1}{3}-\frac{1}{5}\right)=\frac{77}{12}:\frac{11}{4}+\frac{45}{4}.\frac{2}{15}=\frac{7}{3}+\frac{3}{2}=\frac{23}{6}\)
<=>77/12:11/3+45/4(2/15)
=7/4+3/2=13/4
77/12.3/11+45/4.2/15
=7/3+3/2=23/6
\(6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}\cdot\left(\frac{1}{3}-\frac{1}{5}\right)\)\(=2\frac{1}{3}+11\frac{1}{4}\cdot\frac{2}{15}=2\frac{1}{3}+1\frac{1}{2}=3\frac{5}{6}=\frac{23}{6}\)
