`5(x+2)^2=5/9`
`=> (x+2)^2=5/9 : 5`
`=>(x+2)^2= 5/9 xx 5`
`=>(x+2)^2=25/9`
`=>(x+2)^2=(5/3)^2`
`=> x+2=+- 5/3`
\(\Rightarrow\left[{}\begin{matrix}x+2=\dfrac{5}{3}\\x+2=-\dfrac{5}{3}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{3}-2\\x=-\dfrac{5}{3}-2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=-\dfrac{11}{3}\end{matrix}\right.\)
Vậy \(x\in\left\{-\dfrac{1}{3};-\dfrac{11}{3}\right\}\)