\(\left(5x+1\right)^2=\frac{36}{49}\)
\(\left(5x+1\right)^2=\left(\frac{6}{7}\right)^2\)
\(=>5x+1=\frac{6}{7}\)
\(5x=\frac{-1}{7}\)
\(x=\frac{-1}{35}\)
\(\left(2x-1\right)^3=8\)
\(\left(2x-1\right)^3=2^3\)
\(2x-1=2\)
\(2x=3\)
\(x=\frac{3}{2}\)
\(\left(x-\frac{4}{11}\right)^3=343\)
\(\left(x-\frac{4}{11}\right)^3=7^3\)
\(x-\frac{4}{11}=7\)
\(x=7\frac{4}{11}\)
\(\left(3x-2\right)^5=-243\)
\(\left(3x-2\right)^5=\left(-3\right)^5\)
\(3x-2=-3\)
\(3x=-1\)
\(x=\frac{-1}{3}\)
\(\left(5x+1\right)^2=\frac{36}{49}\)
\(\Rightarrow\orbr{\begin{cases}5x+1=\frac{6}{7}\\5x+1=-\frac{6}{7}\end{cases}\Rightarrow\orbr{\begin{cases}x=-\frac{1}{35}\\x=-\frac{13}{35}\end{cases}}}\)
Vậy ...
\(\left(2x-1\right)^3=8\)
\(2x-1=2\)
\(x=\frac{3}{2}\)
Vậy...
\(\left(x-\frac{4}{11}\right)^3=343\)
\(x-\frac{4}{11}=7\)
\(x=\frac{81}{11}\)
Vậy...
\(\left(3x-2\right)^5=-243\)
\(3x-2=-3\)
\(x=-\frac{1}{3}\)
Vậy ...
