\(5x\cdot5^2=10\)
\(\Leftrightarrow5x=\dfrac{2}{5}\)
hay \(x=\dfrac{2}{25}\)
Đúng 1
Bình luận (0)
Các câu hỏi tương tự
1 tìm x
A. 3x-3/2-5x+10/3=1
B.- 1/5x 02/3=1/10 x +5/6
C.3/2(x-5/3)-4/5=x+1
Ai giúp mk vs.Mk đang gấp
1 tìm x
A. 3x-3/2-5x+10/3=1
B.- 1/5x 02/3=1/10 x +5/6
C.3/2(x-5/3)-4/5=x+1
Ai giúp mk vs.Mk đang gấp
|x +10| - (5 - 3x) = (4x - 10) - (x - 5)
|3x + 21| - ( 10 - 5x ) = 5x - |-20|
Tìm x, biết:
a) 5.2²+(x+3)=5²
b)2³+(x-3²)=5³-4³
c)4.(x-5)-2³=2⁴.3
d)5.(x+7)-10=2³.5
e)7²-7.(13-x)=14
f)5x-5²=10
g)9x-2.3²=3⁴
h)10x+2².5=10²
i)125-5.(4+x)=15
j)2⁶+(5+x)=3⁴
X^2+5x-10 chia hét x+5
tìm x
102*105x-2/10x=1000
54x-4/5x*25=1252*5x
x(x+1/2)-1/5x-1/10 / 3 . x(x-1/2)-1/3x+1/6 / 5
x(x+1/2)-1/5x-1/10 / 3 . x(x-1/2)-1/3x+1/6 / 5
Tìm x
1) 5x - 16 = 40 + x
2) 4x - 10 = 15 - x
3) 3x - 6 = 5x + 2
4) 15 - x = 4x - 5
5) x - 15 = 6 + 4x
6) -12 + x = 5x - 20
7) 7x - 4 = 20 + 3x
8) 5x - 7 = -21 - 2x
9) x + 15 = 20 - 4x
10) 17 - x = 7 - 6x