Ta có: \(\dfrac{-5}{6}+\dfrac{8}{3}+\dfrac{29}{-6}\le x\le\dfrac{1}{2}+2+\dfrac{5}{2}\)
\(\Leftrightarrow\dfrac{-5}{6}+\dfrac{16}{6}+\dfrac{-29}{6}\le x\le3+2\)
\(\Leftrightarrow-3\le x\le5\)
\(\Leftrightarrow x\in\left\{-3;-2;-1;0;1;2;3;4;5\right\}\)