53 : 5 + 52 . 102 - 25 . 3
= 10,6 + 5,304 - 75
= 15,904 - 75
= - 59 , 096
= -59 , 096
53 : 5 + 52 . 102 - 25 . 3
= 10,6 + 5,304 - 75
= 15,904 - 75
= - 59 , 096
= -59 , 096
Chứng minh :
\(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{101}\right)\)\(-\)\(\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+\frac{1}{100}+\frac{1}{102}\right)\)\(=\)\(\frac{1}{52}+\frac{1}{53}+...+\frac{1}{100}+\frac{1}{101}+\frac{1}{102}\)
Mik đng cần gấp , giúp mik nha, giải kĩ cho mik nha
Bài 2. Thực hiện các phép tính sau (tính hợp lí nếu có thể):
a) 22.20210 : 11+ [(52 – 2 5 ) : 2]
b) 1024 : 25 + 140 : (38 + 25 ) + 2.32 – 7 23 : 721
c) 100 : {300 : [450 – (4 . 53 – 2 3 . 25)]}
d) (35 + 37 + 39 + 311) : (34 + 36 + 38 + 310)
Mik sẽ tick
CMR
(1+1/3+1/5+......+1/101)-(1/2+1/4+1/6+.......+1/100+1/102)=1/52+1/53+1/54+......+1/100+1/101+1/102
17/21*48/53+17/21*4/53+52/53*4/21
Làm giúp mik với nha
CMR: \(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{101}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+...+ \frac{1}{102}\right)=\frac{1}{52}+\frac{1}{53}+...+\frac{1}{102}\)
a) A= 1+3+32+....+320
b) B=5+52+53+...+510
c) C=24+25+26+...+230
help meee
Chứng tỏ rằng :
(1+1/3+1/5+1/7+......+1/101)-(1/2+1/4+1/6+...+1/100) = 1/52+1/53+1/54+.....+1/100+1/101+1/102
3) 287 + 121 + 513 + 79
4) 17.34 + 17.39 + 27.17
5) 4. 52 – 64: 42
6) 25 . 101 – 25 .1010
7) 72 + [ 62 – ( 102 – 4 . 16 )]
8) 2x – 138 = 23. 32
9) [120 : 4 – (23 -17) . 5]. 20212022
Bài 2.4. Cho 𝐴=1+5+52+53+⋯.+52021. Tìm số tự nhiên 𝑛, biết 4𝐴+1=5𝑛.
giup mik a